/**
 * 344.反转字符串
 * https://leetcode-cn.com/problems/reverse-string/
 *
 * 编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。
 *
 * 不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。
 *
 * 你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。
 *
 * 示例 1：
 * 输入：["h","e","l","l","o"]
 * 输出：["o","l","l","e","h"]
 *
 * 示例 2：
 * 输入：["H","a","n","n","a","h"]
 * 输出：["h","a","n","n","a","H"]
 */
public class Q2 {
    public static void main(String[] args) {
        char[] s = {'h','e','l','l','o'};

        Solution solution = new Solution();
        solution.reverseString(s);
        System.out.println(s);
    }
    static class Solution {
        public void reverseString(char[] s) {
            int i=0, j=s.length-1;
            char temp;
            while(i < j) {
                temp = s[i];
                s[i] = s[j];
                s[j] = temp;
                ++i;
                --j;
            }
        }
    }
    public void reverseString2(char[] s) {
        int i=0, j=s.length-1;
        while(i < j) {
            s[i] = (char)(s[j] ^ s[i]);
            s[j] = (char)(s[j] ^ s[i]);
            s[i] = (char)(s[j] ^ s[i]);
            ++i;
            --j;
        }
    }
}
